template
T foo(T&& a)
{
return a;
}

int main()
{
Point p(0,0);
foo(p);
return 0;
}

And I didn’t get the error which you mentioned in the article:
“error: cannot bind rvalue reference of type ‘MyClass&&’ to lvalue of type ‘MyClass'”
Thank you for explanation and for yours marvelous articles!

Hi Sebastien. The above code is perfectly legal. The state of a moved-from object is said to be “unspecified, but valid”. And since it is valid, you can assign something into it. The unspecified means that if you read from it, you can’t predict what is going to be in it.
Note that unspecified does not mean the same thing as Undefined Behaviour. UB offers no guarantee, like it could halt the program, while with unspecified you just don’t know what value comes out of the object when your read it.

By reusing the resource of the object, I mean that this object is available to be be modified, because it’s going to be destroyed soon and no one can manipulate it until then. Hope that clarifies the meaning!

MyClass x;
f(std::move(x));
x.name = “abc”;
and so on