Comments on: Good news: strong types are (mostly) free in C++

By: Sergey Eliseev

Sergey Eliseev — Fri, 12 May 2017 13:42:00 +0000

I think the NamedType constructor shall be

template
explicit NamedType( Args&&... a ) : value_( std::forward(a)... ) {}

p.s. the comments engine seem to dislike C++ templates 🙂

By: Sergey Eliseev

Sergey Eliseev — Fri, 12 May 2017 13:39:00 +0000

In reply to Dmytro Starosud. Yes, and then using `Width` and `Height` becomes a PITA. So, there's a different cost.

By: Dmytro Starosud

Dmytro Starosud — Mon, 08 May 2017 10:01:00 +0000

Looks expressive. But I would go to the extreme and defer all the raw stuff to the very end.
I mean it’s better to have:

class StrongRectangle
{
public:
StrongRectangle (Width width, Height height) : width_(width), height_(height) {}
Width getWidth() const {return width_;}
Height getHeight() const {return height_;}

private:
Width width_;
Height height_;
};