Comments on: Strong lambdas: strong typing over generic types

By: Jonathan Boccara

Jonathan Boccara — Tue, 03 Oct 2017 12:23:00 +0000

In reply to Maran Pakkirisamy. Sorry, I had missed your comment. You're right and this is now corrected. Thanks!

By: Jonathan Boccara

Jonathan Boccara — Tue, 03 Oct 2017 12:21:00 +0000

In reply to Abhijit Salvi. This is a good question! The using statement brings in the constructors from the base class NamedType. This way, Aggregator can be constructed from a value (here a lambda), like its base class would have been.

By: Abhijit Salvi

Abhijit Salvi — Tue, 03 Oct 2017 09:01:00 +0000

Thank you very much for such great material Jonathan.

I have one curious question though – pardon my ignorance on this one.

In the below snippet:

template
struct Aggregator : NamedType
{
using NamedType::NamedType;
};

I realize that the using statement is necessary; without which the code won’t compile. Can you explain why this is the case (perhaps I’m missing something obvious) ?

Thanks

By: Jonathan Boccara

Jonathan Boccara — Wed, 22 Feb 2017 21:42:00 +0000

Thanks Guillaume!
I updated the article to take your remark into account. Hope this comes through in C++20 then!

By: Maran Pakkirisamy

Maran Pakkirisamy — Wed, 22 Feb 2017 09:42:00 +0000

In the excerpt of call to set_aggregate, the first, compare lambda reads as
p1.first < p2.second;
which I think should read as
p1.first < p2.first;
I crosschecked it here,
https://github.com/joboccara/sets/blob/master/main.cpp:283