Comments on: STL Function objects: Stateless is Stressless

By: Jonathan Boccara

Jonathan Boccara — Sun, 22 Oct 2017 12:19:00 +0000

I mean to say print all numbers while they remain below 10. So the first time we meet 10 or more we stop printing. So I’d say PrintUntilTenOrMore (or PrintWhileLessThanTen) could work, unless I’ve missed something?

And for the lamda, we search the point where a number is 10 or more, so that’s the end point of the first subrange. Again, I may have missed something, but this looks about right, don’t you think?

By: Jean Philippe François

Jean Philippe François — Thu, 19 Oct 2017 13:06:00 +0000

Hello, the name of the functor should not be PrintUntilTenOrLess instead of PrintUntilTenOrMore?

And this piece of code:

auto first10 = std::find_if(numbers.begin(), numbers.end(), [](int number){return number >= 10;});

should it not be

auto first10 = std::find_if(numbers.begin(), numbers.end(), [](int number){return number < 10;});

By: Jonathan Boccara

Jonathan Boccara — Tue, 24 Jan 2017 18:48:00 +0000

In reply to Johel Ernesto Guerrero Peña. Right! Fixed this by replacing with a take_while. Thanks Johel for pointing this out.

By: Johel Ernesto Guerrero Peña

Johel Ernesto Guerrero Peña — Tue, 24 Jan 2017 12:04:00 +0000

As mentioned by skitleer in the reddit thread, the last code fragment prints all numbers less than 10, rather than until the first 10, like the previous ones. So the correct code would be:


for_each(delimit(numbers,10) | transform(f),
         [](int number){std::cout << number << 'n';});